 
    
  
 
Start by calculating the equilibrium constant:
  
 
	The equilibrium constant is related to the equilibrium
	activities by   .  In a
	rigid container at constant temperature,
 .  In a
	rigid container at constant temperature,   .  It
	follows (by stoichiometry) that
 .  It
	follows (by stoichiometry) that   .  We therefore get the quadratic equation
 .  We therefore get the quadratic equation
	
  
 
or
  
 
This equation has two solutions:
  
 
	One solution (  ) leads to a negative activity for the nitrogen dioxide
	and is therefore physically inadmissible.
	The other solution is
 ) leads to a negative activity for the nitrogen dioxide
	and is therefore physically inadmissible.
	The other solution is   which gives
  which gives
	  .  Thus the equilibrium ratio of
 .  Thus the equilibrium ratio of
	  to
  to   is 0.92.
  is 0.92.
  
 
	  at the boiling point.  At
	the normal boiling point,
  at the boiling point.  At
	the normal boiling point,   .
	Thus we have
 .
	Thus we have
	
  
 
or
  
 
This temperature is sufficiently high that liquid water could still exist on this planet.
  
 
  
 
  
 
 , which is the equilibrium constant for the process
 , which is the equilibrium constant for the process
	  
 
  
 
The equilibrium constant at 298K is therefore
  
 
Therefore
  
 
	at 298K, giving us a   of 10.1.
  of 10.1.
	To get the   , we need to know the equilibrium
	constant at this temperature.  For this we need
 , we need to know the equilibrium
	constant at this temperature.  For this we need
	  .
 .
	
  
 
  
 
This reaction can be made to yield more product if it is coupled to a reaction with a very negative free energy change which produces phosphate such as ATP hydrolysis:
  
 
The overall process is
  
 
  
 
	Maximum transport (requiring the minimum ratio of ATP to ADP) is achieved
	when   , i.e. when
 , i.e. when
	
  
 
However,
  
 
	In the biochemists' standard state,   ,
 ,   and
  and   .
	Therefore
 .
	Therefore
	
  
 
