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Total value of this section: 80
-   State the first and second laws of thermodynamics.	[4 marks]
-   Give an example of a natural phenomenon for which classical mechanics
	has no explanation but which can be explained using quantum
	mechanics.
	[2 marks]
-   Using   as an example, explain the difference between
	bonding and antibonding molecular orbitals.	[5 marks] as an example, explain the difference between
	bonding and antibonding molecular orbitals.	[5 marks]
-   Do you expect   to be a stable molecule?  Explain
	briefly.	[4 marks] to be a stable molecule?  Explain
	briefly.	[4 marks]
-   What is the ground state electronic configuration of a scandium
	atom?
	[4 marks]
-   How much heat is released or absorbed when 50g of sodium
	hydroxide is dissolved in water?	[6 marks]
-   -   One of the diamond industry's favorite advertising lines
		is that ``diamonds are forever''.  A reasonable
		thermodynamic interpretation of this line is that
		the reaction
		   
 
		is not spontaneous under normal
		conditions.  Is this true?
		[2 marks] 
-   In reactions which involve only solids or liquids, we
		generally ignore any terms proportional to PV, such as
		the work.  Calculate the work
		done when one mole of diamond is converted to one mole
		of graphite at 298K under a constant pressure of
		1atm.  Based on your calculation, would it normally be
		acceptable to neglect the work?  The density of diamond
		is   while the density of graphite is while the density of graphite is .
		[8 marks] .
		[8 marks]
-   Calculate   , , and and for the conversion of diamond
		to graphite at for the conversion of diamond
		to graphite at accurately.
		[12 marks] accurately.
		[12 marks]
-   Calculate   for the conversion of
		diamond to graphite at for the conversion of
		diamond to graphite at using the approximation that using the approximation that and and are
		approximately constant and equal to their values at
		298K.  Compare your answer to that obtained in the
		last part of this question.  If you had not had enough
		data to do a detailed calculation and had been forced to
		use the approximate method, would the free energy change
		obtained have been of any value?	[3 marks] are
		approximately constant and equal to their values at
		298K.  Compare your answer to that obtained in the
		last part of this question.  If you had not had enough
		data to do a detailed calculation and had been forced to
		use the approximate method, would the free energy change
		obtained have been of any value?	[3 marks]
 
-   The solubility of nitrogen in water at   under
		a pressure of pure nitrogen of 1atm is under
		a pressure of pure nitrogen of 1atm is .  Calculate the free energy
		of formation of an aqueous nitrogen molecule.	[5 marks] .  Calculate the free energy
		of formation of an aqueous nitrogen molecule.	[5 marks]
-   The solubility of nitrogen in water at
		  is is .
		Calculate the enthalpy of formation of an aqueous
		nitrogen molecule.	[5 marks] .
		Calculate the enthalpy of formation of an aqueous
		nitrogen molecule.	[5 marks]
 
-   Suppose that an electron in a box makes a transition from the
	ground state to the first excited state while absorbing a photon
	of wavelength 250nm.  What is the length of the box?	[10 marks]
-  Some cells take in phosphate by reacting it with ADP to form ATP (and
	water).  This fulfills two cellular needs simultaneously, namely
	phosphate uptake and ATP synthesis, but the process is not
	spontaneous under realistic conditions.  The driving force is
	provided by the spontaneous flow of protons across the cell
	membrane.  The pH outside the cell is typically lower than the pH
	inside by 1.5 units.  Three protons flow
	into the cell for every phosphate transported in.
	If the concentration of phosphate outside the cell is   and
	the concentration of ADP inside the cell is and
	the concentration of ADP inside the cell is , what is the maximum concentration of
	ATP which can be reached inside the cell at 298K due to this
	process alone?
	For the reaction , what is the maximum concentration of
	ATP which can be reached inside the cell at 298K due to this
	process alone?
	For the reaction , , at 298K.
	[10 marks] at 298K.
	[10 marks]
   
 Next: Answer any two questions 
Up: Chemistry 2720 Fall 1998 
 Previous: Chemistry 2720 Fall 1998 
Marc Roussel 
Fri Dec 18 21:22:47 MST 1998