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Quiz 3 solution

Consider the following diagram:

tex2html_wrap78

The path consisting of steps 1, 2 and 3 produces the same overall change as the freezing of ice at tex2html_wrap_inline71 . All we need to do is to calculate tex2html_wrap_inline73 for each step and then add them up:

eqnarray28

This is significantly different from the enthalpy change at tex2html_wrap_inline75 . Fortunately, for chemical reactions (but not for phase changes, as this example shows), the variation of enthalpy change with temperature is much less than this because the difference in heat capacities between reactants and products is not normally as large as it is for ice and water. Accordingly, we can usually behave as if the enthalpy changes were constant.



Marc Roussel
Thu Oct 1 11:07:27 MDT 1998