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Solutions to the Practice Problem on Electrochemistry

  1. (The steps are numbered sequentially so the numbers don't correspond directly to those from the procedure taught in class.)
    1. tex2html_wrap_inline247
      tex2html_wrap_inline249
    2. tex2html_wrap_inline251
      tex2html_wrap_inline253
    3. tex2html_wrap_inline255
    1. A heat engine converts heat to work so we need to calculate the heat produced by the reaction. At constant pressure, this is just tex2html_wrap_inline257 . The reaction is

      displaymath259

      eqnarray38

      The efficiency of the heat engine is

      displaymath261

      The efficiency is related to the maximum work by tex2html_wrap_inline263 so the maximum work done, per mole of methanol burned is

      displaymath265

    2. A fuel cell is an isothermal free energy machine that carries out oxidation under controlled conditions. Thus free energy considerations limit the maximum work that can be done. The reaction which occurs in the fuel cell is

      displaymath267

      (Note the different states of methanol and water in this case. If operated well below tex2html_wrap_inline269 , fuel cells produce liquid water.) We start by calculating tex2html_wrap_inline271 :

      eqnarray71

      Then we calculate tex2html_wrap_inline273 itself:

      eqnarray87

      The maximum work which can be obtained from this fuel cell is 702.3kJ/mol, or almost twice as much as we get from the methanol heat engine.

    3. From the oxygen half-reaction, we see that it takes four electrons per oxygen molecule reduced. In our reaction, we have tex2html_wrap_inline275 oxygen molecules so oxidizing methanol requires the transfer of tex2html_wrap_inline277 electrons. Therefore

      displaymath279

  2. The half-reactions are

    displaymath281

    and

    displaymath283

    The spontaneous overall reaction is the one with a positive value of tex2html_wrap_inline285 . Since the tex2html_wrap_inline287 term of the Nernst equation is generally a small correction, we guess

    displaymath289

    (If we have guessed wrong, we will get a negative voltage and we will know that the spontaneous reaction in fact runs in the opposite direction.) The ionic strength of the zinc sulfate solution is

    displaymath291

    Therefore, the mean activity coefficient at 298K is found by

    eqnarray140

    The ionic strength of the copper sulfate solution is

    displaymath293

    Therefore, the mean activity coefficient at 298K is found by

    eqnarray152

    We then compute the electrochemical potential from the Nernst equation:

    eqnarray161

    We probably should not have used Debye-Hückel theory because the ionic strength of the zinc sulfate solution is a little beyond the range in which Debye-Hückel theory is accurate.


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Marc Roussel
Thu Nov 28 14:03:44 MST 1996