 
    
  
 
	The maximum ratio of PEP to pyruvate is obtained when
	  , so we want
 , so we want
	
  
 
The activity of phosphate is irrelevant (at least, in this problem) so we have
  
 
This is not a very large ratio, but it is considerably better than what would be obtained without ATP and may be sufficient if only a small amount of phosphoenolpyruvate is needed.
 .  We begin by
			computing the equilibrium constant at 298K:
 .  We begin by
			computing the equilibrium constant at 298K:
			  
 
At the boiling point, K=1. (Make sure you understand why that is before proceeding.) We use the formula which relates equilibrium constants to temperature, which we rearrange to the form
  
 
 .
			This implies that
 .
			This implies that   .  Therefore
 .  Therefore
			  .
			(This is Trouton's rule.)
			Since we can calculate
 .
			(This is Trouton's rule.)
			Since we can calculate   (as
			above) and
  (as
			above) and   , we can compute
			the temperature T at which
 , we can compute
			the temperature T at which
			  , i.e. the boiling
			point:
 , i.e. the boiling
			point:
			  
 
 for essentially the same reason:
		Both assume that
  for essentially the same reason:
		Both assume that   is independent of
		temperature, which is not quite right.  The second
		method also assumes that
  is independent of
		temperature, which is not quite right.  The second
		method also assumes that   is
		independent of temperature.
  is
		independent of temperature.
	 and
  and   , so
 , so
	  .  Since H=E+PV,
 .  Since H=E+PV,
	  
 
	Therefore
	  .
 .
Note: If I put a differential derivation on a test or exam, it will be an optional question. If you learn how to do these, they are quite easy. However, make sure that you can at least interpret a differential (i.e. relate the differential to derivatives of state functions) that is given to you.
  
 
		where T is in Kelvin and the entropy is in
		  .
 .
 :
 :
		  
 
		where   .
 .
  
 
		The approximation is valid to 1% for   up to
		about 80K, although the approximation is better on the
		high-temperature side than on the low-T side.
  up to
		about 80K, although the approximation is better on the
		high-temperature side than on the low-T side.
	
 .  (This is somewhat arbitrary and you could
	of course pick a different number.)
	To obtain a conservative estimate of the maximum ionic strength
	for ideal behaviour, take the largest reasonable values for
 .  (This is somewhat arbitrary and you could
	of course pick a different number.)
	To obtain a conservative estimate of the maximum ionic strength
	for ideal behaviour, take the largest reasonable values for
	  and
  and   :  There are few anions stable in solution whose
	charges are other than -1 or -2 so take
 :  There are few anions stable in solution whose
	charges are other than -1 or -2 so take   .  There are
	some +3 and +4 cations so take
 .  There are
	some +3 and +4 cations so take   .  The critical ionic
	strength is therefore
 .  The critical ionic
	strength is therefore
	  
 
	Below an ionic strength of   , we can be
	reasonably assured of ideal behaviour.  We also know that above
	0.01mol/L, the Debye-Hückel equation yields poor results so
	we should use Debye-Hückel theory when
 , we can be
	reasonably assured of ideal behaviour.  We also know that above
	0.01mol/L, the Debye-Hückel equation yields poor results so
	we should use Debye-Hückel theory when
	  .
 .
  
 
or
  
 
	Since the charges on the calcium and oxalate ions are +2 and
	-2,   .  Accordingly
 .  Accordingly
	
  
 
	Start iteration with the guesstimate   :
 :
	
  
 
	The molar mass of calcium oxalate is 128.10g/mol so the
	solubility is   .
	Note that the ionic strength of the saturated solution is
 .
	Note that the ionic strength of the saturated solution is
	  , which is well within the
	range of applicability of Debye-Hückel theory.
 , which is well within the
	range of applicability of Debye-Hückel theory.
 .  Using the freezing-point depression formula,
        the total concentration of solutes should therefore
        be
 .  Using the freezing-point depression formula,
        the total concentration of solutes should therefore
        be
          
 
        Since NaCl dissociates into   and
  and   ,
        this is twice the concentration of either sodium or chloride
        ions (i.e. twice the formal concentration of sodium chloride).
        The formal concentration of sodium chloride should therefore be
        1.4mol/kg.
        We have 18000kg of solvent so
 ,
        this is twice the concentration of either sodium or chloride
        ions (i.e. twice the formal concentration of sodium chloride).
        The formal concentration of sodium chloride should therefore be
        1.4mol/kg.
        We have 18000kg of solvent so
        
  
 
  
 
        In the more conventional concentration units, this is
          .  Since 100mL of water
        (0.100L) of water was used, the number of moles of the
        forensic sample is
 .  Since 100mL of water
        (0.100L) of water was used, the number of moles of the
        forensic sample is   .
        The mass was 2.841mg so the molar mass of the unknown
        substance is
 .
        The mass was 2.841mg so the molar mass of the unknown
        substance is
        
  
 
From the chemical formula, we know that the molar mass of MDA is 179.218g/mol. It seems quite likely that the material brought in by the police officer is MDA. Further tests on the sample should be ordered.
