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Chemistry 2720, Fall 96, Assignment 1 Solutions

  1. tex2html_wrap_inline174 To get work in Joules (the SI unit of energy), we must transform the external pressure to Pascals and tex2html_wrap_inline176 to cubic meters:

    eqnarray9

    displaymath178

  2. We need to calculate the amount of heat required to raise the water's temperature from 20 to tex2html_wrap_inline180 C. 1.5L is tex2html_wrap_inline182 . Using the density of water at tex2html_wrap_inline184 C, we find

    displaymath186

    The heat required to bring the water to its boiling point is therefore

    eqnarray29

    This heat is supplied by a 1500W heating element. A Watt is a Joule per second so

    displaymath188

    tex2html_wrap236

  3. To make each lead sphere:
    1. You have to solidify the molten lead. This requires the removal of tex2html_wrap_inline190 of heat, i.e. the water gains this much heat.
    2. The spheres cool from tex2html_wrap_inline192 C to tex2html_wrap_inline194 C. Relative to the lead spheres, this process yields tex2html_wrap_inline196 of heat. Thus the water gains tex2html_wrap_inline198 .
    Overall, the water gains tex2html_wrap_inline200 . The heat gained by the water in going from 20 to tex2html_wrap_inline202 C is

    displaymath204

    Therefore

    displaymath206

    tex2html_wrap238

  4. The work done on each box is tex2html_wrap_inline208 . There are 24 boxes so the total work done is 3.5kJ. Relative to the person doing the lifting, tex2html_wrap_inline210 . To compensate for this energy use, the person must take in at least 3.5kJ of usable (catabolizable) energy in the form of food. Carbohydrates provide 4.0kcal/g which is 16.7kJ/g. Therefore

    displaymath212

    Note that this calculation assumes 100% efficiency of all the processes involved (muscle work, extraction of nutrients from food, etc.). Nevertheless, it's safe to conclude that it won't be necessary to eat double portions.

    tex2html_wrap240

    1. First, balance the reaction:

      displaymath214

      For this reaction,

      eqnarray104

      tex2html_wrap242

    2. By definition, tex2html_wrap_inline218 . Therefore tex2html_wrap_inline220 For ideal gases, PV=nRT while for solids and liquids, the product PV is insignificantly small. Accordingly,

      displaymath226

      where tex2html_wrap_inline228 is the change in the number of moles of gas during the reaction. For this reaction (as written), there are tex2html_wrap_inline230 reactant molecules and 2 product molecules so tex2html_wrap_inline232 . That gives

      eqnarray132

      tex2html_wrap244


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Up: Back to the old Chemistry 2720 index

Marc Roussel
Tue Oct 15 15:49:35 MDT 1996