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Chemistry 2710 Review Problems: Hints and Answers

    1. The tex2html_wrap_inline76 can be used to calculate the concentration of a product. The initial rate is tex2html_wrap_inline78 .
    1. With this much data, it's best to use a graphical method. It simplifies certain calculations is you convert the tex2html_wrap_inline80 to tex2html_wrap_inline82 . The order of the reaction is 1. The rate constant is tex2html_wrap_inline84 .
    2. Not elementary. Hint: It has something to do with the rate law.
    1. tex2html_wrap_inline86 with tex2html_wrap_inline88
  1. tex2html_wrap_inline90
  2. tex2html_wrap_inline92
  3. Because the initial concentrations are equal and the stoichiometry is 1:1, the two concentrations will always be equal, making this an instance of a simple rate law. The concentration after 10min is 0.038mol/L.
  4. tex2html_wrap_inline94
    1. tex2html_wrap_inline96
    2. tex2html_wrap_inline97 . Your answer may look a little different from mine, but you should get the same results in the next part if you did this right.
    3. The following table shows the half-life computed for a few different initial conditions:

      tabular43

  5. You have to do a little stoichiometry to determine the pressure of A: tex2html_wrap_inline114 where tex2html_wrap_inline116 is the initial pressure of A (400mmHg). You need another equation which related tex2html_wrap_inline118 and tex2html_wrap_inline120 to P. The reaction is of the second order. Since I didn't tell you what units I want the rate constant in, you might as well use the pressure units I gave you and save yourself a little trouble: tex2html_wrap_inline124 .
  6. This has something to do with plotting a line.
  7. The 47 decays per day is 47 atoms that undergo reaction per day. Since this is a first-order process, tex2html_wrap_inline126 where k is the rate constant and N is the number of atoms of tex2html_wrap_inline132 in the sample. The half-life is tex2html_wrap_inline134 .
    1. Plot ln P vs t, the slope is the specific growth rate of the population (k). The doubling time computed from k is 77y.
    2. Prediction is tricky. My fit of the data is

      displaymath144

      We are looking for the t at which tex2html_wrap_inline148 . I get about 2005. However, if you plot all the data, you will see that the graph of tex2html_wrap_inline150 vs t has considerable curvature. The population growth is in fact slowing down. If I refit only the data from the last two decades (which should give a much more accurate estimate of the current rate of growth), I predict that the Finnish population will reach 6 million in 2031.

    3. See above.

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Up: Back to the Chemistry 2710 assignment index

Marc Roussel
Fri Feb 18 10:23:19 MST 2000