Chemistry 2000, Fall 96
Assignment 1 Solutions

  1. Take a logarithm (log or ln) or both sides of the equation and use the rule tex2html_wrap_inline120 to get the tex2html_wrap_inline122 out of the exponent:

    displaymath124

    tex2html_wrap168

  2. We can get rid of the logarithm by using the fact that tex2html_wrap_inline128 is the inverse function of tex2html_wrap_inline130 :

    displaymath132

    tex2html_wrap168

    Would you believe that I didn't do it on purpose? The brain works in mysterious ways.

  3. In the first solution,

    displaymath136

    In the second solution,

    displaymath138

    The number of moles of chloride in the mixture is the sum of the amounts in each solution so tex2html_wrap_inline140 . We also need the number of moles of water. There is a total of 20mL of water. This corresponds to

    displaymath142

    The mole fraction of the chloride ions is therefore

    eqnarray41

    tex2html_wrap172

  4. Sodium sulphate is Na tex2html_wrap_inline146 SO tex2html_wrap_inline148 . The number of moles of Na tex2html_wrap_inline146 SO tex2html_wrap_inline148 formula units is

    displaymath154

    Multiply this last number by two to get the number of sodium ions. tex2html_wrap174

  5. To compute the derivative at t=1, use the data to either side of this point:

    eqnarray65

    We do this for each point which is bracketed by two others to obtain the table

    tabular79

    The graph has the following appearance: tex2html_wrap176

    The points lie on a beautifully straight line. This is not a coincidence.



Marc Roussel
Sat Sep 14 00:28:55 MDT 1996