August 19, 2007
This session is based on the material in section 2.1 of Kelley's "The Humongous Book of Calculus Problems"
The section presents a series of problems involving simplifying expressions containing powers and square roots.
Problem 2.1

In[1]:=

Simplify[x^2y^3x^4y^6x^9y^8]

Out[1]=

x^15 y^17

In[2]:=

Simplify[(w^10x^6y^3z^8)/(w^2x^4y^7z^10)]

Out[2]=

(w^8 x^2)/(y^4 z^2)

In[3]:=

Simplify[((4x)/(7y^3))^-2]

Out[3]=

(49 y^6)/(16 x^2)

In[4]:=

Simplify[((x^-2y^6)^3)/(3xy^-5)^-2]

Out[4]=

(9 y^18)/(x^6 xy^10)

Nope. Let's try this again, paying very close attention to the parentheses.

In[5]:=

Simplify[(((x^-2) y^6)^3)/((3x (y^-5))^-2)]

Out[5]=

(9 y^8)/x^4

Good. I must ensure that parentheses enclose both the entire numerator and the entire denominator.

In[6]:=

Simplify[Sqrt[72x^5y^8]]

Out[6]=

6 2^(1/2) (x^5 y^8)^(1/2)

This is strange. The third term can be simplified further. Let's play with this for a moment.

In[7]:=

Sqrt[x^5y^8]

Out[7]=

(x^5 y^8)^(1/2)

In[8]:=

Sqrt[(x^5y^8)]

Out[8]=

(x^5 y^8)^(1/2)

In[9]:=

Simplify[Sqrt[x^2]]

Out[9]=

x^2^(1/2)

In[10]:=

(x^2)^(1/2)

Out[10]=

x^2^(1/2)

In[11]:=

Simplify[(x^2)^(1/2)]

Out[11]=

x^2^(1/2)

Fascinating. This does not appear to simplify to x.
There is another command called FullSimplify. Let's try that.

In[12]:=

FullSimplify[(x^2)^(1/2)]

Out[12]=

x^2^(1/2)

Nope. That doesn't do it either.

In[13]:=

FullSimplify[Sqrt[x^2]]

Out[13]=

x^2^(1/2)

Okay. Mathematica is correct. This last expression does not simplify if x is a complex number. However if x is restricted to the real numbers, then we get the following:

In[14]:=

Simplify[Sqrt[x^2], x∈Reals]

Out[14]=

Abs[x]

Perfect.

In[15]:=

Simplify[(-8x^7y^5z^2)^(1/3)]

Out[15]=

2 (-x^7 y^5 z^2)^(1/3)

In[16]:=

FullSimplify[(-8x^7y^5z^2)^(1/3)]

Out[16]=

2 (-x^7 y^5 z^2)^(1/3)

In[18]:=

FullSimplify[(-8x^7y^5z^2)^(1/3), x∈Reals]

Out[18]=

2 (-x^7 y^5 z^2)^(1/3)

In[19]:=

Simplify[(-8x^7y^5z^2)^(1/3), x>0]

Out[19]=

2 (-x^7 y^5 z^2)^(1/3)

In[20]:=

250^(2/3)

Out[20]=

25 2^(2/3)

Conclusion. Simplifying complex expressions involving powers sometimes fails to totally simplify the expression. I am not sure if this is a weakness with Mathematica or whether there is some subtle mathematics that says that such expressions do not simplify further. Note that Mathematica does not give a wrong answer - it simply fails to simplify the expression as far as one would expect.


Created by Mathematica  (August 19, 2007) Valid XHTML 1.1!