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Chemistry 2720 Spring 1998 Test 2 Solutions

  1. The reaction is

    displaymath271

    Start by calculating the equilibrium constant:

    eqnarray10

    The equilibrium constant is related to the equilibrium activities by tex2html_wrap_inline273 . In a rigid container at constant temperature, tex2html_wrap_inline275 . It follows (by stoichiometry) that tex2html_wrap_inline277 . We therefore get the quadratic equation

    displaymath279

    or

    displaymath281

    This equation has two solutions:

    displaymath283

    One solution ( tex2html_wrap_inline285 ) leads to a negative activity for the nitrogen dioxide and is therefore physically inadmissible. The other solution is tex2html_wrap_inline287 which gives tex2html_wrap_inline289 . Thus the equilibrium ratio of tex2html_wrap_inline291 to tex2html_wrap_inline293 is 0.92.

  2. For the process

    displaymath295

    tex2html_wrap_inline297 at the boiling point. At the normal boiling point, tex2html_wrap_inline300 . Thus we have

    displaymath301

    or

    eqnarray50

    This temperature is sufficiently high that liquid water could still exist on this planet.

    1.   We can read this off directly from the differential of A:

      eqnarray70

    2. We start with the answer to question 3a:

      eqnarray75

    3. For an ideal gas, P = nRT/V so

      displaymath307

  3. We need tex2html_wrap_inline309 , which is the equilibrium constant for the process

    displaymath311

    eqnarray99

    The equilibrium constant at 298K is therefore

    displaymath313

    Therefore

    displaymath315

    at 298K, giving us a tex2html_wrap_inline317 of 10.1.

    To get the tex2html_wrap_inline317 , we need to know the equilibrium constant at this temperature. For this we need tex2html_wrap_inline321 .

    eqnarray126

    1. Two reactions are coupled if they can be made to occur together in such a way that one reaction drives the other. This requires that the overall free energy change for the two reactions taken together be negative. For example, fructose-6-phosphate is made from fructose by reaction with phosphate:

      displaymath323

      This reaction can be made to yield more product if it is coupled to a reaction with a very negative free energy change which produces phosphate such as ATP hydrolysis:

      displaymath325

      The overall process is

      displaymath327

    2. Le Chatelier's principle states that a chemical system will react in such a way as to partially offset an applied stress. For example, increasing the temperature shifts the equilibrium of exothermic reactions toward the reactants because exothermic reactions absorb heat when reactants are formed from the products. Coupled reactions also rely on Le Chatelier's principle: In the example above, we might say that production of fructose-6-phosphate is increased because ATP hydrolysis supplies one of the reactants of the other reaction. The system responds by reacting away some of this phosphate.
  4. The overall process is

    displaymath329

    Maximum transport (requiring the minimum ratio of ATP to ADP) is achieved when tex2html_wrap_inline331 , i.e. when

    displaymath333

    However,

    eqnarray182

    In the biochemists' standard state, tex2html_wrap_inline335 , tex2html_wrap_inline337 and tex2html_wrap_inline339 . Therefore

    displaymath341


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Up: Back to the old Chemistry 2720 index

Marc Roussel
Mon Mar 23 21:28:43 MST 1998